Python urllib2 error 505 version not supported

' The gateway server did not receive a timely response' ), 505: ( ' HTTP Version Not Supported', ' Cannot fulfill request. request は URLs ( Uniform Resource Locators) を取得するための Python モジュールです。. しかし HTTP の URL を開くときにエラーが起きたり、 特殊なケース に遭遇すると、 HyperText Transfer Protocol に関するいくつかのことを理解する必要が あります。. high load' ), 504: ( ' Gateway Timeout', ' The gateway server did not receive a timely response' ), 505: ( ' HTTP Version Not Supported', ' Cannot fulfill request. That error is due to the server that u are trying to access does not support your request HTTP versión, so you need to change it. May be, you need to send 1. import urllib2, httplib httplib. _ http_ vsn = 10 httplib. しかし HTTP の URL を開くときにエラーが起きたり、 特殊なケースに遭遇すると、 HyperText Transfer Protocol に関するいくつかのことを理解する必要があります。. デフォルトでは urllib2 は自身の情報を Python- urllib/ x. y として扱います ( x と y は Python のリリースバージョンのメジャーバージョン、. usr/ bin/ env python try: from httplib import HTTPConnection from urllib2 import HTTPHandler, build_ opener except ImportError: # Python 3 from http. client import HTTPConnection from urllib.

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    Python supported version

    request import HTTPHandler,. Right now, I' m using urlopen( ). Do I need to use another method of opening the webpage? I read something about having to use httplib. HTTPError: HTTP Error 505: HTTP Version Not Supported. I' m using urllib2 module to fetch a URL from a server which understands. 1 only ( no HTTP/ 1. urlopen( ) results in " urllib2. HTTPError: HTTP Error 505: HTTP Version not supported". How do I force urllib2 to t sure, what is going wrong, but when I try to do the same action using requests library, it works:. from urllib import quote url = yahooapis. com/ v1/ public/ yql? q= select * from geo.

    places where text = \ ' Boston\ ' '.